2(5x^2+11x-8)=16

Solution for 2(5x^2+11x-8)=16 equation:

2(5x^2+11x-8)=16

We move all terms to the left:

2(5x^2+11x-8)-(16)=0

We multiply parentheses

10x^2+22x-16-16=0

We add all the numbers together, and all the variables

10x^2+22x-32=0

a = 10; b = 22; c = -32;
Δ = b2-4ac
Δ = 222-4·10·(-32)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-42}{2*10}=\frac{-64}{20}
=-3+1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+42}{2*10}=\frac{20}{20}
=1
$